What is the solution for y^'-2xy-8=0 ?

The solution for y^'-2xy-8=0 is y=4sqrt(pi)\erf(x)e^{x^2}+c_{1}e^{x^2}

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y^'-2xy-8=0

y^{^{'}} - 2 x y - 8 = 0

y = 4 π erf (x) e^{x^{2}} + c_{1} e^{x^{2}}

Solution steps

y^{'} (x) - 2 x y - 8 = 0

Solve linear ODE:

y = 4 π erf (x) e^{x^{2}} + c_{1} e^{x^{2}}

y = 4 π erf (x) e^{x^{2}} + c_{1} e^{x^{2}}

e^{3 (t + 1)}

y = x (3 x - 2)^{4}

\int x^{2} (4 + x^{3}) d x

x y^{^{'}} + y = 5 x y^{2}

What is the solution for y^'-2xy-8=0 ?
The solution for y^'-2xy-8=0 is y=4sqrt(pi)\erf(x)e^{x^2}+c_{1}e^{x^2}