What is the tangent of f(x)=(5x)/(x+3),2,\at x=2 ?

The tangent of f(x)=(5x)/(x+3),2,\at x=2 is y= 3/5 x+4/5

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tangent of f(x)=(5x)/(x+3),2,\at x=2

tangent of

f (x) = \frac{5 x}{x + 3}, 2, at x = 2

y = \frac{3}{5} x + \frac{4}{5}

Solution steps

Find the tangent point:

(2, 2)

Find the slope of

f (x) = \frac{5 x}{x + 3} : \frac{df ( x )}{d x} = \frac{15}{( x + 3 ) ^{2}}

Compute the slope of

f (x) = \frac{5 x}{x + 3}

x = 2 : m = \frac{3}{5}

Find the line with slope m=

\frac{3}{5}

and passing through

(2, 2) : y = \frac{3}{5} x + \frac{4}{5}

y = \frac{3}{5} x + \frac{4}{5}

\frac{d}{d x} (2^{a r c t a n (x)})

\int (x + 1)^{2} e^{- 2 x} d x

\frac{\partial}{\partial x} (cos^{6} (x^{2} y^{9}))

\frac{d}{d x} (3 x^{2} + x y + 2 x + y)

cos (x), \frac{π}{2}

What is the tangent of f(x)=(5x)/(x+3),2,\at x=2 ?
The tangent of f(x)=(5x)/(x+3),2,\at x=2 is y= 3/5 x+4/5