What is the tangent of x^4+xy^2=5,(1,2) ?

The tangent of x^4+xy^2=5,(1,2) is y=-2x+4

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tangent of x^4+xy^2=5,(1,2)

tangent of

x^{4} + x y^{2} = 5, (1, 2)

y = - 2 x + 4

Solution steps

Find the slope of

x^{4} + x y^{2} = 5 : \frac{d y}{d x} = \frac{- 4 x ^{3} - y ^{2}}{2 x y}

Compute the slope of

x^{4} + x y^{2} = 5

(1, 2) : m = - 2

Find the line with slope m=

- 2

and passing through

(1, 2) : y = - 2 x + 4

y = - 2 x + 4

\frac{d}{d x} (4 x - \frac{2}{x ^{3}})

\frac{\partial}{\partial x} (\frac{x}{x + y} + e^{x y} x + 4 y)

\frac{d}{d x} (\frac{x - x ^{2}}{x})

\frac{d}{d x} (2 cos (\frac{x}{2}))

- 4 (x - 9)^{3}

What is the tangent of x^4+xy^2=5,(1,2) ?
The tangent of x^4+xy^2=5,(1,2) is y=-2x+4