What is the derivative of y=(x^2+1)^3 ?

The derivative of y=(x^2+1)^3 is 6x(x^2+1)^2

What is the first derivative of y=(x^2+1)^3 ?

The first derivative of y=(x^2+1)^3 is 6x(x^2+1)^2

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derivative of

y = (x^{2} + 1)^{3}

6 x (x^{2} + 1)^{2}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{3})

Apply the chain rule:

3 (x^{2} + 1)^{2} \frac{d}{d x} (x^{2} + 1)

= 3 (x^{2} + 1)^{2} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 3 (x^{2} + 1)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} + 1)^{2}

\int \frac{1 + cos ( 2 x )}{sin ^{2} ( 2 x )} d x

\frac{\partial}{\partial y} (x + 3 y)

(- 1.3) (3.5)

g (x) = ln^{3} (x)

y = \frac{5 x}{2 ^{x}}, at x = 2

What is the derivative of y=(x^2+1)^3 ?
The derivative of y=(x^2+1)^3 is 6x(x^2+1)^2
What is the first derivative of y=(x^2+1)^3 ?
The first derivative of y=(x^2+1)^3 is 6x(x^2+1)^2