What is the limit as x approaches 0+of arctan(1/x) ?

The limit as x approaches 0+of arctan(1/x) is pi/2

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limit as x approaches 0+of arctan(1/x)

x \to 0 + lim (arctan (\frac{1}{x}))

\frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

x \to 0 + lim (arctan (\frac{1}{x}))

Apply the Limit Chain Rule:

\frac{π}{2}

= \frac{π}{2}

\int_{- 2}^{0} (u^{5} - u^{3} + u^{2}) d u

\int_{1}^{2} 2 r^{4} ln (r) d r

x \to 2 lim (csc (\frac{π x}{6}))

\frac{d ^{10}}{d x ^{10}} ((2 x + 5)^{7})

\int \frac{x ^{2}}{x ^{2} + 2 x + 1} d x

What is the limit as x approaches 0+of arctan(1/x) ?
The limit as x approaches 0+of arctan(1/x) is pi/2