What is the sum from n=5 to infinity of tan(1/n) ?

The sum from n=5 to infinity of tan(1/n) is diverges

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sum from n=5 to infinity of tan(1/n)

n = 5 \sum \infty tan (\frac{1}{n})

diverges

Solution steps

n = 5 \sum \infty tan (\frac{1}{n})

Apply Series Limit Comparison Test:

diverges

= diverges

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f (x) = x^{4} + 8 x^{2} - x, (1, 8)

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\int_{0}^{2} \frac{1}{2 - x} d x

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What is the sum from n=5 to infinity of tan(1/n) ?
The sum from n=5 to infinity of tan(1/n) is diverges