What is the limit as x approaches 0 of arccos(x) ?

The limit as x approaches 0 of arccos(x) is pi/2

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limit as x approaches 0 of arccos(x)

x \to 0 lim (arccos (x))

\frac{π}{2}

Solution steps

x \to 0 lim (arccos (x))

Plug in the value

x = 0

= arccos (0)

Use the following trivial identity:

arccos (0) = \frac{π}{2}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{2}

x \to \infty lim (6 x)

\int 5 sin^{3} (x) cos^{2} (x) d x

f (x) = arcsin (6 x + 1)

\int y^{2} z^{3} d x

\frac{\partial}{\partial x} (4 ln (\frac{3 x y}{7 z}))

What is the limit as x approaches 0 of arccos(x) ?
The limit as x approaches 0 of arccos(x) is pi/2