What is (\partial)/(\partial x)(2xy^2+4) ?

The answer to (\partial)/(\partial x)(2xy^2+4) is 2y^2

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(\partial)/(\partial x)(2xy^2+4)

\frac{\partial}{\partial x} (2 x y^{2} + 4)

2 y^{2}

Solution steps

\frac{\partial}{\partial x} (2 x y^{2} + 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y^{2}) + \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (2 x y^{2}) = 2 y^{2}

\frac{\partial}{\partial x} (4) = 0

= 2 y^{2} + 0

Simplify

= 2 y^{2}

w \to \infty lim (\frac{2 w ^{2} - 3 w + 4}{5 w ^{2} + 7 w - 1})

y^{^{''}} - k y = 0

x \to - 2 lim ((x - 6)^{\frac{2}{3}})

y^{^{'}} = 0.2 ln (\frac{2000}{y}) y

\frac{d}{d x} (\frac{6}{1 + cos ( x )})

What is (\partial)/(\partial x)(2xy^2+4) ?
The answer to (\partial)/(\partial x)(2xy^2+4) is 2y^2