What is the derivative of y=\sqrt[5]{x^3}-x^pi ?

The derivative of y=\sqrt[5]{x^3}-x^pi is (3x^2)/(5(x^3)^{4/5)}-pix^{pi-1}

What is the first derivative of y=\sqrt[5]{x^3}-x^pi ?

The first derivative of y=\sqrt[5]{x^3}-x^pi is (3x^2)/(5(x^3)^{4/5)}-pix^{pi-1}

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derivative of

\frac{3 x ^{2}}{5 ( x ^{3} ) ^{\frac{4}{5}}} - π x^{π - 1}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x^{π}) = π x^{π - 1}

= \frac{3 x ^{2}}{5 ( x ^{3} ) ^{\frac{4}{5}}} - π x^{π - 1}

\frac{d}{d x} (\frac{7 x}{x ^{2} + 49})

\frac{d ^{4}}{d x ^{4}} (4 e^{x^{2}})

\int \frac{3}{x ^{2} ( x - 1 )} d x

\frac{\partial}{\partial x} (y^{2} ln (x))

\int \frac{x ^{6} - 5 x}{x ^{4}} d x

What is the derivative of y=\sqrt[5]{x^3}-x^pi ?
The derivative of y=\sqrt[5]{x^3}-x^pi is (3x^2)/(5(x^3)^{4/5)}-pix^{pi-1}
What is the first derivative of y=\sqrt[5]{x^3}-x^pi ?
The first derivative of y=\sqrt[5]{x^3}-x^pi is (3x^2)/(5(x^3)^{4/5)}-pix^{pi-1}