What is (d^2)/(dx^2)(log_{10}(x)) ?

The answer to (d^2)/(dx^2)(log_{10}(x)) is -1/(ln(10)x^2)

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(d^2)/(dx^2)(log_{10}(x))

\frac{d ^{2}}{d x ^{2}} (lo g_{10} (x))

- \frac{1}{ln ( 10 ) x ^{2}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (lo g_{10} (x))

\frac{d}{d x} (lo g_{10} (x)) = \frac{1}{x ln ( 10 )}

= \frac{d}{d x} (\frac{1}{x ln ( 10 )})

\frac{d}{d x} (\frac{1}{x ln ( 10 )}) = - \frac{1}{ln ( 10 ) x ^{2}}

= - \frac{1}{ln ( 10 ) x ^{2}}

(5 x)^{\frac{1}{3}}

\frac{d}{d x} (\frac{- 4 x ^{5} - 2 π ^{2}}{x ^{7}})

\int 1 - cos (2 x) d x

\frac{1}{s ^{2} + 2 s}

\int u^{6} d u

What is (d^2)/(dx^2)(log_{10}(x)) ?
The answer to (d^2)/(dx^2)(log_{10}(x)) is -1/(ln(10)x^2)