What is the solution for 6x^{''}+1960x=0,x(0)=-3,x^'(0)=0 ?

The solution for 6x^{''}+1960x=0,x(0)=-3,x^'(0)=0 is x=-3cos((14sqrt(5)t)/(sqrt(3)))

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6x^{''}+1960x=0,x(0)=-3,x^'(0)=0

6 x^{^{''}} + 1960 x = 0, x (0) = - 3, x^{^{'}} (0) = 0

x = - 3 cos (\frac{14 5 t}{3})

Solution steps

6 x^{''} (t) + 1960 x = 0

Solve linear ODE:

x = - 3 cos (\frac{14 5 t}{3})

x = - 3 cos (\frac{14 5 t}{3})

f (x) = (3)^{x}, at x = 8

x \to 2 lim (2^{c \cdot x})

\frac{d}{d x} (\frac{6 x}{2 x ^{\frac{1}{3}}})

y^{^{''}} + y = sin (x)

\int_{0}^{1} 40 \frac{1}{x ^{p}} d x

What is the solution for 6x^{''}+1960x=0,x(0)=-3,x^'(0)=0 ?
The solution for 6x^{''}+1960x=0,x(0)=-3,x^'(0)=0 is x=-3cos((14sqrt(5)t)/(sqrt(3)))