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Popular >

xy^'-y+1=0

Solution

x y^{^{'}} - y + 1 = 0

Solution

y = c_{1} x + 1

Solution steps

x y^{'} (x) - y + 1 = 0

Solve separable ODE:

y = c_{1} x + 1

y = c_{1} x + 1

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Frequently Asked Questions (FAQ)

What is the solution for xy^'-y+1=0 ?
The solution for xy^'-y+1=0 is y=c_{1}x+1