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Popular >

y^'=xy^2+2xy

Solution

y^{^{'}} = x y^{2} + 2 x y

Solution

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

Solution steps

y^{'} (x) = x y^{2} + 2 x y

Solve Bernoulli ODE:

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

Popular Examples

sum from n=1 to infinity of 1/(n^{2/3)}

n = 1 \sum \infty \frac{1}{n ^{\frac{2}{3}}}

integral of 6^{(x-2)}

\int 6^{(x - 2)} d x

integral of 1/(sqrt(5-x^2-4x))

\int \frac{1}{5 - x ^{2} - 4 x} d x

x^3(dy)/(dx)=y^2+1

x^{3} \frac{d y}{d x} = y^{2} + 1

integral of (12)/((x^2-6x+13)^2)

\int \frac{12}{( x ^{2} - 6 x + 13 ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy^2+2xy ?
The solution for y^'=xy^2+2xy is y= 2/(e^{-x^2-c_{1)}-1}