What is (\partial)/(\partial x)((x-1)^2*(y+4)^2) ?

The answer to (\partial)/(\partial x)((x-1)^2*(y+4)^2) is 2(y+4)^2(x-1)

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(\partial)/(\partial x)((x-1)^2*(y+4)^2)

\frac{\partial}{\partial x} ((x - 1)^{2} \cdot (y + 4)^{2})

2 (y + 4)^{2} (x - 1)

Solution steps

\frac{\partial}{\partial x} ((x - 1)^{2} (y + 4)^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (y + 4)^{2} \frac{\partial}{\partial x} ((x - 1)^{2})

Apply the chain rule:

2 (x - 1) \frac{\partial}{\partial x} (x - 1)

= 2 (x - 1) \frac{\partial}{\partial x} (x - 1)

\frac{\partial}{\partial x} (x - 1) = 1

= (y + 4)^{2} \cdot 2 (x - 1) \cdot 1

Simplify

= 2 (y + 4)^{2} (x - 1)

y^{^{''}} + 4 y^{^{'}} + 4 y = e^{- 2 t}

f (x) = x 3 - 2 x^{2}

y^{^{'}} = - y, y (0) = 1

g (x) = \frac{2 x + 2}{x ^{2} + 2}

n = 0 \sum \infty n

What is (\partial)/(\partial x)((x-1)^2*(y+4)^2) ?
The answer to (\partial)/(\partial x)((x-1)^2*(y+4)^2) is 2(y+4)^2(x-1)