What is area 19-x^2,-2x+16,-5,-sqrt(19) ?

The answer to area 19-x^2,-2x+16,-5,-sqrt(19) is (125-19sqrt(19))/3+3sqrt(19)-9

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area 19-x^2,-2x+16,-5,-sqrt(19)

area

19 - x^{2}, - 2 x + 16, - 5, - 19

\frac{125 - 19 19}{3} + 319 - 9

Decimal Notation

18.13700 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{- 19} 19 - x^{2} - (- 2 x + 16) d x

Solve

\int_{- 5}^{- 19} 19 - x^{2} - (- 2 x + 16) d x : \frac{125 - 19 19}{3} + 319 - 9

The area is:

= \frac{125 - 19 19}{3} + 319 - 9

\frac{\partial}{\partial x} (y \cdot ∣ x ∣)

(x^{2} + 1) y^{^{'}} + 9 x (y - 1) = 0, y (0) = 2

\frac{d P}{d t} - a P = b

d x + e^{9 x} d y = 0

\frac{d}{d x} (- 2 x - 3 x^{3})

What is area 19-x^2,-2x+16,-5,-sqrt(19) ?
The answer to area 19-x^2,-2x+16,-5,-sqrt(19) is (125-19sqrt(19))/3+3sqrt(19)-9