What is the first derivative of 5x-9 ?

The first derivative of 5x-9 is 5

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derivative of 5x-9

\frac{d}{d x} (5 x - 9)

5

Solution steps

\frac{d}{d x} (5 x - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x) - \frac{d}{d x} (9)

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (9) = 0

= 5 - 0

Simplify

= 5

y^{^{''}} - 5 y^{^{'}} + 6 y = sin (x)

\int sec^{2} (3 θ) d θ

x \to 8 - lim (\frac{x}{ln ( 9 - x )})

\frac{d}{d x} (arctan (x - 1))

y^{^{'}} - (\frac{2 x}{( 1 + x ^{2} )}) y = 0