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Popular >

xy^'+y=e^x,y(1)=6

Solution

x y^{^{'}} + y = e^{x}, y (1) = 6

Solution

y = \frac{e ^{x}}{x} + \frac{6 - e}{x}

Solution steps

x y^{'} (x) + y = e^{x}

Solve linear ODE:

y = \frac{e ^{x}}{x} + \frac{6 - e}{x}

y = \frac{e ^{x}}{x} + \frac{6 - e}{x}

Popular Examples

integral of 9/(6+9x)

\int \frac{9}{6 + 9 x} d x

integral of (2^x+e^pi)

\int (2^{x} + e^{π}) d x

derivative of e^7 derivative of

e^{7}

d x + e^{3} x d y = 0

tangent of f(x)=x^2,(-1,-3)tangent of

f (x) = x^{2}, (- 1, - 3)

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=e^x,y(1)=6 ?
The solution for xy^'+y=e^x,y(1)=6 is y=(e^x)/x+(6-e)/x