What is the first derivative of 2x+1 ?

The first derivative of 2x+1 is 2

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derivative of 2x+1

derivative of

2 x + 1

2

Solution steps

\frac{d}{d x} (2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 + 0

Simplify

= 2

y^{^{''}} - 3 y^{^{'}} + 18 y = 0

\int (x - 2) (x - 3)^{6} d x

\frac{\partial}{\partial x} (4 (x - y) e^{4 y + 2 x^{2}})

f (x) = x^{3} - 1

\frac{\partial}{\partial x} (4 x^{3} - 5 x^{2} + 8 x)