What is (\partial)/(\partial x)(2yx-3y+y^2) ?

The answer to (\partial)/(\partial x)(2yx-3y+y^2) is 2y

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(\partial)/(\partial x)(2yx-3y+y^2)

\frac{\partial}{\partial x} (2 y x - 3 y + y^{2})

2 y

Solution steps

\frac{\partial}{\partial x} (2 y x - 3 y + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y x) - \frac{\partial}{\partial x} (3 y) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (2 y x) = 2 y

\frac{\partial}{\partial x} (3 y) = 0

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 y - 0 + 0

Simplify

= 2 y

y e^{x y} d x + x e^{x y} d y = 0

\frac{d}{d x} (\frac{a}{b x ^{2}})

2 x

\frac{( s - 10 )}{( s ^{2} - 2 s - 3 )}

\frac{d y}{d x}, x^{6} - 5 x y^{3} = 9 x y

What is (\partial)/(\partial x)(2yx-3y+y^2) ?
The answer to (\partial)/(\partial x)(2yx-3y+y^2) is 2y