What is the tangent of f(x)=7x^3+5x,\at x=7 ?

The tangent of f(x)=7x^3+5x,\at x=7 is y=1034x-4802

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tangent of f(x)=7x^3+5x,\at x=7

tangent of

f (x) = 7 x^{3} + 5 x, at x = 7

y = 1034 x - 4802

Solution steps

Find the tangent point:

(7, 2436)

Find the slope of

f (x) = 7 x^{3} + 5 x : \frac{df ( x )}{d x} = 21 x^{2} + 5

Compute the slope of

f (x) = 7 x^{3} + 5 x

x = 7 : m = 1034

Find the line with slope m=

1034

and passing through

(7, 2436) : y = 1034 x - 4802

y = 1034 x - 4802

\frac{d}{d x} (3 e^{x} (5 x^{5} - 2))

y^{'} = sin^{2} (x - y)

\frac{d}{d x} ((x^{2} + 3)^{4})

\frac{d}{d x} (5 e^{x})

\frac{\partial}{\partial x} ((3 x^{2} + 3 x - 1) (2 x + 3))

What is the tangent of f(x)=7x^3+5x,\at x=7 ?
The tangent of f(x)=7x^3+5x,\at x=7 is y=1034x-4802