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Popular >

7y^{''}+4y^'=0

Solution

7 y^{^{''}} + 4 y^{^{'}} = 0

Solution

y = c_{1} + c_{2} e^{- \frac{4 t}{7}}

Solution steps

7 y^{''} (t) + 4 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{4 t}{7}}

y = c_{1} + c_{2} e^{- \frac{4 t}{7}}

Popular Examples

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\int (t^{2} + 2)^{3} d t

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y = 4 x^{2}

limit as x approaches-2 of (x^2-1)(7x+3)

x \to - 2 lim ((x^{2} - 1) (7 x + 3))

inverse oflaplace 1/(s^2(s-1))inverse laplace

\frac{1}{s ^{2} ( s - 1 )}

Frequently Asked Questions (FAQ)

What is the solution for 7y^{''}+4y^'=0 ?
The solution for 7y^{''}+4y^'=0 is y=c_{1}+c_{2}e^{-(4t)/7}