What is the derivative of f(x)=(4x)/(e^x) ?

The derivative of f(x)=(4x)/(e^x) is (4(1-x))/(e^x)

What is the first derivative of f(x)=(4x)/(e^x) ?

The first derivative of f(x)=(4x)/(e^x) is (4(1-x))/(e^x)

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derivative of

f (x) = \frac{4 x}{e ^{x}}

\frac{4 ( 1 - x )}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{4 x}{e ^{x}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} e ^{x} - \frac{d}{d x} ( e ^{x} ) x}{( e ^{x} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 4 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}} : \frac{4 ( 1 - x )}{e ^{x}}

= \frac{4 ( 1 - x )}{e ^{x}}

35 x ln (20 x)

\int (15 x^{- 2} - 5 x) cos (6 x^{- 1} + x^{2}) d x

\int 2^{s} d s

\frac{d y}{d x} = y - 3

y^{^{''}} - 10 y^{^{'}} + y = 0

What is the derivative of f(x)=(4x)/(e^x) ?
The derivative of f(x)=(4x)/(e^x) is (4(1-x))/(e^x)
What is the first derivative of f(x)=(4x)/(e^x) ?
The first derivative of f(x)=(4x)/(e^x) is (4(1-x))/(e^x)