What is the tangent of f(x)=3x^2+9x^3-5x,\at x=-4 ?

The tangent of f(x)=3x^2+9x^3-5x,\at x=-4 is y=403x+1104

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=3x^2+9x^3-5x,\at x=-4

tangent of

f (x) = 3 x^{2} + 9 x^{3} - 5 x, at x = - 4

y = 403 x + 1104

Solution steps

Find the tangent point:

(- 4, - 508)

Find the slope of

f (x) = 3 x^{2} + 9 x^{3} - 5 x : \frac{df ( x )}{d x} = 6 x + 27 x^{2} - 5

Compute the slope of

f (x) = 3 x^{2} + 9 x^{3} - 5 x

x = - 4 : m = 403

Find the line with slope m=

403

and passing through

(- 4, - 508) : y = 403 x + 1104

y = 403 x + 1104

\frac{1}{2 ( s + 2 )}

x + 3

\frac{d}{d s} (\frac{3}{s ^{2} + 9})

\int arctan (x) d x

cos^{2} (t) \frac{d y}{d t} = 1

What is the tangent of f(x)=3x^2+9x^3-5x,\at x=-4 ?
The tangent of f(x)=3x^2+9x^3-5x,\at x=-4 is y=403x+1104