What is the integral of (cos(2x))^2 ?

The integral of (cos(2x))^2 is 1/2 (x+1/4 sin(4x))+C

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integral of (cos(2x))^2

\int (cos (2 x))^{2} d x

\frac{1}{2} (x + \frac{1}{4} sin (4 x)) + C

Solution steps

\int (cos (2 x))^{2} d x

Rewrite using trig identities

= \int \frac{1}{2} (1 + cos (4 x)) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int 1 + cos (4 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int 1 d x + \int cos (4 x) d x)

\int 1 d x = x

\int cos (4 x) d x = \frac{1}{4} sin (4 x)

= \frac{1}{2} (x + \frac{1}{4} sin (4 x))

Add a constant to the solution

= \frac{1}{2} (x + \frac{1}{4} sin (4 x)) + C

\int \frac{( x - 2 )}{x} d x

x \to \infty lim (x \cdot (- 1))

\int (5 - x)^{2} d x

f (x) = x^{2} - 2 x - 4, at x = 2

\frac{\partial}{\partial t} (sin (x - a t))

What is the integral of (cos(2x))^2 ?
The integral of (cos(2x))^2 is 1/2 (x+1/4 sin(4x))+C