What is the solution for 5(dx)/(dt)+10x=120sin(60t) ?

The solution for 5(dx)/(dt)+10x=120sin(60t) is x=(12(sin(60t)-30cos(60t)))/(901)+(c_{1})/(e^{2t)}

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5(dx)/(dt)+10x=120sin(60t)

5 \frac{d x}{d t} + 10 x = 120 sin (60 t)

x = \frac{12 ( sin ( 60 t ) - 30 cos ( 60 t ) )}{901} + \frac{c _{1}}{e ^{2 t}}

Solution steps

5 \frac{d x}{d t} + 10 x = 120 sin (60 t)

Solve linear ODE:

x = \frac{12 ( sin ( 60 t ) - 30 cos ( 60 t ) )}{901} + \frac{c _{1}}{e ^{2 t}}

x = \frac{12 ( sin ( 60 t ) - 30 cos ( 60 t ) )}{901} + \frac{c _{1}}{e ^{2 t}}

f (x) = \frac{1}{x - 2}, at x = 6

\int \frac{1}{2 sin ( x ) - cos ( x ) + 5} d x

\frac{d}{d x} ((5)^{x})

\frac{\partial}{\partial x} (x^{n})

What is the solution for 5(dx)/(dt)+10x=120sin(60t) ?
The solution for 5(dx)/(dt)+10x=120sin(60t) is x=(12(sin(60t)-30cos(60t)))/(901)+(c_{1})/(e^{2t)}