What is the derivative of cos(bx) ?

The derivative of cos(bx) is -sin(bx)b

What is the first derivative of cos(bx) ?

The first derivative of cos(bx) is -sin(bx)b

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\frac{d}{d x} (cos (b x))

- sin (b x) b

Solution steps

\frac{d}{d x} (cos (b x))

Apply the chain rule:

- sin (b x) \frac{d}{d x} (b x)

= - sin (b x) \frac{d}{d x} (b x)

\frac{d}{d x} (b x) = b

= - sin (b x) b

\int k x^{2} d x

x \cdot ln (x), 1

\int (- 3 \cdot cos (x) + 4 \cdot sec^{2} (x)) d x

\int \frac{1}{a - b x} d x

y = x^{2} - 1

What is the derivative of cos(bx) ?
The derivative of cos(bx) is -sin(bx)b
What is the first derivative of cos(bx) ?
The first derivative of cos(bx) is -sin(bx)b