What is the derivative of (6x/(sqrt(x^2+2))) ?

The derivative of (6x/(sqrt(x^2+2))) is (12)/((x^2+2)sqrt(x^2+2))

What is the first derivative of (6x/(sqrt(x^2+2))) ?

The first derivative of (6x/(sqrt(x^2+2))) is (12)/((x^2+2)sqrt(x^2+2))

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\frac{d}{d x} (\frac{6 x}{x ^{2} + 2})

\frac{12}{( x ^{2} + 2 ) x ^{2} + 2}

Solution steps

\frac{d}{d x} (\frac{6 x}{x ^{2} + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{x}{x ^{2} + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 6 \cdot \frac{\frac{d x}{d x} x ^{2} + 2 - \frac{d}{d x} ( x ^{2} + 2 ) x}{( x ^{2} + 2 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 2) = \frac{x}{x ^{2} + 2}

= 6 \cdot \frac{1 \cdot x ^{2} + 2 - \frac{x}{x ^{2} + 2} x}{( x ^{2} + 2 ) ^{2}}

Simplify

6 \cdot \frac{1 \cdot x ^{2} + 2 - \frac{x}{x ^{2} + 2} x}{( x ^{2} + 2 ) ^{2}} : \frac{12}{( x ^{2} + 2 ) x ^{2} + 2}

= \frac{12}{( x ^{2} + 2 ) x ^{2} + 2}

\int t^{2} - cos (2 π) t d t

\int sin^{2} (d) t

\frac{d}{d x} ((16 x)^{3})

f (x) = - 2 sin (2 x)

\int x^{4} - 2 x^{2} + 1 d x

What is the derivative of (6x/(sqrt(x^2+2))) ?
The derivative of (6x/(sqrt(x^2+2))) is (12)/((x^2+2)sqrt(x^2+2))
What is the first derivative of (6x/(sqrt(x^2+2))) ?
The first derivative of (6x/(sqrt(x^2+2))) is (12)/((x^2+2)sqrt(x^2+2))