What is the tangent of 2y^3+xy-y=250x^4,(1,5) ?

The tangent of 2y^3+xy-y=250x^4,(1,5) is y= 199/30 x-49/30

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tangent of 2y^3+xy-y=250x^4,(1,5)

tangent of

2 y^{3} + x y - y = 250 x^{4}, (1, 5)

y = \frac{199}{30} x - \frac{49}{30}

Solution steps

Find the slope of

2 y^{3} + x y - y = 250 x^{4} : \frac{d y}{d x} = \frac{1000 x ^{3} - y}{6 y ^{2} + x - 1}

Compute the slope of

2 y^{3} + x y - y = 250 x^{4}

(1, 5) : m = \frac{199}{30}

Find the line with slope m=

\frac{199}{30}

and passing through

(1, 5) : y = \frac{199}{30} x - \frac{49}{30}

y = \frac{199}{30} x - \frac{49}{30}

\frac{d}{d x} ((1 - cos (x))^{2})

\int 5 x ln (x^{6}) d x

x \to 1 lim (3 x^{3} - 2 x^{2} + 4)

\int \frac{x ^{2} + 2 x}{x ^{3} - x ^{2} + x - 1} d x

y (θ) = \frac{π}{9} cos (θ)

What is the tangent of 2y^3+xy-y=250x^4,(1,5) ?
The tangent of 2y^3+xy-y=250x^4,(1,5) is y= 199/30 x-49/30