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Popular >

integral of-8/(y^9)

Solution

\int - \frac{8}{y ^{9}} d y

Solution

\frac{1}{y ^{8}} + C

Solution steps

\int - \frac{8}{y ^{9}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 8 \cdot \int \frac{1}{y ^{9}} d y

Apply the Power Rule

: - \frac{1}{8 y ^{8}}

= - 8 (- \frac{1}{8 y ^{8}})

Simplify

- 8 (- \frac{1}{8 y ^{8}}) : \frac{1}{y ^{8}}

= \frac{1}{y ^{8}}

Add a constant to the solution

= \frac{1}{y ^{8}} + C

Popular Examples

integral of (3x+2)/(x^3-x^2-2x)

\int \frac{3 x + 2}{x ^{3} - x ^{2} - 2 x} d x

area y=x^2-1,y=-x+2,x=0,x=1 area

y = x^{2} - 1, y = - x + 2, x = 0, x = 1

integral of 3/(x^4)+2-3/(x^2)

\int \frac{3}{x ^{4}} + 2 - \frac{3}{x ^{2}} d x

derivative of 9xsin(x^2)

\frac{d}{d x} (9 x sin (x^{2}))

y^{^{''}} + 9 y^{^{'}} = 0

Frequently Asked Questions (FAQ)

What is the integral of-8/(y^9) ?
The integral of-8/(y^9) is 1/(y^8)+C