What is the solution for (dx)/(dt)=x-2x^2 ?

The solution for (dx)/(dt)=x-2x^2 is x=-(e^{t+c_{1}})/(1-2e^{t+c_{1)}}

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(dx)/(dt)=x-2x^2

\frac{d x}{d t} = x - 2 x^{2}

x = - \frac{e ^{t + c_{1}}}{1 - 2 e ^{t + c_{1}}}

Solution steps

\frac{d x}{d t} = x - 2 x^{2}

Solve separable ODE:

x = - \frac{e ^{t + c_{1}}}{1 - 2 e ^{t + c_{1}}}

x = - \frac{e ^{t + c_{1}}}{1 - 2 e ^{t + c_{1}}}

\frac{1}{5}

x^{2}, x, [\frac{1}{4}, 1]

\frac{d}{d x} (x^{2} arctan (3 x))

y = 1 + 2 x, y = \frac{( 3 + x )}{3}

\frac{d}{d x} ((2 x - 3)^{4} (x^{2} + x + 1)^{5})

What is the solution for (dx)/(dt)=x-2x^2 ?
The solution for (dx)/(dt)=x-2x^2 is x=-(e^{t+c_{1}})/(1-2e^{t+c_{1)}}