What is area y=x^3-2x^2+2,y=3x^2+5x-23,-1,7 ?

The answer to area y=x^3-2x^2+2,y=3x^2+5x-23,-1,7 is (832-50sqrt(5))/3+50sqrt(5)-204

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area y=x^3-2x^2+2,y=3x^2+5x-23,-1,7

area

y = x^{3} - 2 x^{2} + 2, y = 3 x^{2} + 5 x - 23, - 1, 7

\frac{832 - 50 5}{3} + 505 - 204

Decimal Notation

147.86893 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{7} x^{3} - 2 x^{2} + 2 - (3 x^{2} + 5 x - 23) d x

Solve

\int_{- 1}^{7} x^{3} - 2 x^{2} + 2 - (3 x^{2} + 5 x - 23) d x : \frac{832 - 50 5}{3} + 505 - 204

The area is:

= \frac{832 - 50 5}{3} + 505 - 204

\frac{\partial}{\partial x} (x^{2} e^{- \frac{x}{y}})

\int_{1}^{5} \frac{e ^{\frac{x}{2}}}{x ^{3}} d x

3 e^{x}, 3 x e^{x^{2}}, [0, 1]

x \to 6 lim (2 x - 7)

\int \frac{( x + 6 )}{( x + 1 )} d x

What is area y=x^3-2x^2+2,y=3x^2+5x-23,-1,7 ?
The answer to area y=x^3-2x^2+2,y=3x^2+5x-23,-1,7 is (832-50sqrt(5))/3+50sqrt(5)-204