What is the derivative of sqrt(3-8x) ?

The derivative of sqrt(3-8x) is -4/(sqrt(3-8x))

What is the first derivative of sqrt(3-8x) ?

The first derivative of sqrt(3-8x) is -4/(sqrt(3-8x))

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\frac{d}{d x} (3 - 8 x)

- \frac{4}{3 - 8 x}

Solution steps

\frac{d}{d x} (3 - 8 x)

Apply the chain rule:

\frac{1}{2 3 - 8 x} \frac{d}{d x} (3 - 8 x)

= \frac{1}{2 3 - 8 x} \frac{d}{d x} (3 - 8 x)

\frac{d}{d x} (3 - 8 x) = - 8

= \frac{1}{2 3 - 8 x} (- 8)

Simplify

\frac{1}{2 3 - 8 x} (- 8) : - \frac{4}{3 - 8 x}

= - \frac{4}{3 - 8 x}

\int \frac{2 x ^{2} + x + 3}{( x + 1 ) ( x ^{2} + 1 )} d x

4^{- x^{8}}

\int 2 sin^{2} (x) d x

x^{3} + y^{2} x^{4} + 4 y^{^{'}} = 0

\int_{0}^{x} (e^{- t^{2}}) d t

What is the derivative of sqrt(3-8x) ?
The derivative of sqrt(3-8x) is -4/(sqrt(3-8x))
What is the first derivative of sqrt(3-8x) ?
The first derivative of sqrt(3-8x) is -4/(sqrt(3-8x))