What is the derivative of 7/(2x^2) ?

The derivative of 7/(2x^2) is -7/(x^3)

What is the first derivative of 7/(2x^2) ?

The first derivative of 7/(2x^2) is -7/(x^3)

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derivative of

\frac{7}{2 x ^{2}}

- \frac{7}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{7}{2 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{7}{2} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{7}{2} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{7}{2} (- 2 x^{- 2 - 1})

Simplify

\frac{7}{2} (- 2 x^{- 2 - 1}) : - \frac{7}{x ^{3}}

= - \frac{7}{x ^{3}}

x \to \infty lim (arctan (x^{6} - x^{9}))

y = arctan (3 x)

f (x) = \frac{3 + 4 x ^{\frac{1}{2}}}{2 + x ^{\frac{3}{2}}}

\int \frac{x ^{2}}{( 5 - x ^{2} ) ^{3}} d x

n = 0 \sum \infty cos (πn)

What is the derivative of 7/(2x^2) ?
The derivative of 7/(2x^2) is -7/(x^3)
What is the first derivative of 7/(2x^2) ?
The first derivative of 7/(2x^2) is -7/(x^3)