What is the derivative of ln(x^3-2x^2+2) ?

The derivative of ln(x^3-2x^2+2) is (3x^2-4x)/(x^3-2x^2+2)

What is the first derivative of ln(x^3-2x^2+2) ?

The first derivative of ln(x^3-2x^2+2) is (3x^2-4x)/(x^3-2x^2+2)

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Popular >

\frac{d}{d x} (ln (x^{3} - 2 x^{2} + 2))

\frac{3 x ^{2} - 4 x}{x ^{3} - 2 x ^{2} + 2}

Solution steps

\frac{d}{d x} (ln (x^{3} - 2 x^{2} + 2))

Apply the chain rule:

\frac{1}{x ^{3} - 2 x ^{2} + 2} \frac{d}{d x} (x^{3} - 2 x^{2} + 2)

= \frac{1}{x ^{3} - 2 x ^{2} + 2} \frac{d}{d x} (x^{3} - 2 x^{2} + 2)

\frac{d}{d x} (x^{3} - 2 x^{2} + 2) = 3 x^{2} - 4 x

= \frac{1}{x ^{3} - 2 x ^{2} + 2} (3 x^{2} - 4 x)

Simplify

\frac{1}{x ^{3} - 2 x ^{2} + 2} (3 x^{2} - 4 x) : \frac{3 x ^{2} - 4 x}{x ^{3} - 2 x ^{2} + 2}

= \frac{3 x ^{2} - 4 x}{x ^{3} - 2 x ^{2} + 2}

\int sec^{4} (x) tan^{4} (x) d x

f (x) = (x^{3} + 7 x^{2} + 5)^{5}

\frac{d}{d x} ((x + 1)^{- \frac{1}{2}})

\frac{d}{d x} (cos (e^{x^{2}}))

\int \frac{sin ( x )}{2 x} d x

What is the derivative of ln(x^3-2x^2+2) ?
The derivative of ln(x^3-2x^2+2) is (3x^2-4x)/(x^3-2x^2+2)
What is the first derivative of ln(x^3-2x^2+2) ?
The first derivative of ln(x^3-2x^2+2) is (3x^2-4x)/(x^3-2x^2+2)