What is the integral of x^3e^{12x} ?

The integral of x^3e^{12x} is 1/3456 e^{12x}(288x^3-72x^2+12x-1)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x^3e^{12x}

\int x^{3} e^{12 x} d x

\frac{1}{3456} e^{12 x} (288 x^{3} - 72 x^{2} + 12 x - 1) + C

Solution steps

\int x^{3} e^{12 x} d x

Apply u-substitution

: \int \frac{e ^{u} u ^{3}}{20736} d u

= \int \frac{e ^{u} u ^{3}}{20736} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{20736} \cdot \int e^{u} u^{3} d u

Apply Integration By Parts

: u^{3} e^{u} - \int 3 u^{2} e^{u} d u

= \frac{1}{20736} (u^{3} e^{u} - \int 3 u^{2} e^{u} d u)

\int 3 u^{2} e^{u} d u = 3 (u^{2} e^{u} - 2 (e^{u} u - e^{u}))

= \frac{1}{20736} (u^{3} e^{u} - 3 (u^{2} e^{u} - 2 (e^{u} u - e^{u})))

Substitute back

u = 12 x

= \frac{1}{20736} ((12 x)^{3} e^{12 x} - 3 ((12 x)^{2} e^{12 x} - 2 (e^{12 x} \cdot 12 x - e^{12 x})))

Simplify

\frac{1}{20736} ((12 x)^{3} e^{12 x} - 3 ((12 x)^{2} e^{12 x} - 2 (e^{12 x} \cdot 12 x - e^{12 x}))) : \frac{1}{3456} e^{12 x} (288 x^{3} - 72 x^{2} + 12 x - 1)

= \frac{1}{3456} e^{12 x} (288 x^{3} - 72 x^{2} + 12 x - 1)

Add a constant to the solution

= \frac{1}{3456} e^{12 x} (288 x^{3} - 72 x^{2} + 12 x - 1) + C

\frac{d}{d x} ((x^{4} + 3 x)^{- 1})

\frac{s - 1}{( s + 1 ) ( s + 2 ) s}

f (x) = \frac{5}{x ^{5}}

f (x) = sin (x), 0

x^{2} + x + 3, [1, 3]

What is the integral of x^3e^{12x} ?
The integral of x^3e^{12x} is 1/3456 e^{12x}(288x^3-72x^2+12x-1)+C