What is area x^2+y^2=4,x^2+y^2=4x ?

The answer to area x^2+y^2=4,x^2+y^2=4x is No Solution

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area x^2+y^2=4,x^2+y^2=4x

area

x^{2} + y^{2} = 4, x^{2} + y^{2} = 4 x

No Solution

Solution steps

Isolate

y

for

x^{2} + y^{2} = 4 : y = 4 - x^{2}, y = - 4 - x^{2}

Isolate

y

for

x^{2} + y^{2} = 4 x : y = 4 x - x^{2}, y = - 4 x - x^{2}

f_{1} (x) = 4 - x^{2}

f_{2} (x) = - 4 - x^{2}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

4 - x^{2} = - 4 - x^{2} : x = 2, x = - 2

4 - x^{2} = 4 x - x^{2} : x = 1

4 - x^{2} = - 4 x - x^{2} :

No Solution for

x \in R

- 4 - x^{2} = 4 x - x^{2} :

No Solution for

x \in R

- 4 - x^{2} = - 4 x - x^{2} : x = 1

4 x - x^{2} = - 4 x - x^{2} : x = 0, x = 4

Curves not bounded

= No Solution

\frac{d}{d y} (\frac{y ^{\frac{3}{2}}}{5})

\int \frac{( x ^{2} + 1 - 2 x ) ^{\frac{1}{5}}}{1 - x} d x

\int \frac{x ^{6}}{1 - x ^{14}} d x

\int 3 cot^{4} (x) d x

\frac{d}{d x} (5 x - 1)

What is area x^2+y^2=4,x^2+y^2=4x ?
The answer to area x^2+y^2=4,x^2+y^2=4x is No Solution