What is the tangent of f(x)=x^2-2x ?

The tangent of f(x)=x^2-2x is y=(2a_{0}-2)x-a_{0}^2

Popular >

tangent of f(x)=x^2-2x

tangent of

f (x) = x^{2} - 2 x

y = (2 a_{0} - 2) x - a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 2 a_{0})

Find the slope of

f (x) = x^{2} - 2 x : \frac{df ( x )}{d x} = 2 x - 2

Compute the slope of

f (x) = x^{2} - 2 x

x = a_{0} : m = 2 a_{0} - 2

Find the line with slope m=

2 a_{0} - 2

and passing through

(a_{0}, a_{0}^{2} - 2 a_{0}) : y = (2 a_{0} - 2) x - a_{0}^{2}

y = (2 a_{0} - 2) x - a_{0}^{2}

\int \frac{x ^{3}}{x ^{2} + 9} d x

\frac{d}{d x} (\frac{- 2 x ^{2} - 2}{( x - 1 ) ^{2} ( x + 1 ) ^{2}})

x = (y - 1)^{2}, x = 13 - y^{2}

\int \frac{2 x}{e ^{2 x}} d x

x \to 2 + lim (g (x))

What is the tangent of f(x)=x^2-2x ?
The tangent of f(x)=x^2-2x is y=(2a_{0}-2)x-a_{0}^2