What is the derivative of tan(x-x+1) ?

The derivative of tan(x-x+1) is tan^2(x)

What is the first derivative of tan(x-x+1) ?

The first derivative of tan(x-x+1) is tan^2(x)

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\frac{d}{d x} (tan (x) - x + 1)

tan^{2} (x)

Solution steps

\frac{d}{d x} (tan (x) - x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (tan (x)) - \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= sec^{2} (x) - 1 + 0

Simplify

sec^{2} (x) - 1 + 0 : tan^{2} (x)

= tan^{2} (x)

\frac{d}{d x} (1 + x^{256} - 1)

y^{^{''}} - 6 y^{^{'}} = 9 t

f (x) = 19 x e^{x}

\int sin (x) e^{3 x} d x

\int x^{2} cos (\frac{1}{9} x) d x

What is the derivative of tan(x-x+1) ?
The derivative of tan(x-x+1) is tan^2(x)
What is the first derivative of tan(x-x+1) ?
The first derivative of tan(x-x+1) is tan^2(x)