What is the tangent of f(x)=(2x-1)/(x+1),\at x=4 ?

The tangent of f(x)=(2x-1)/(x+1),\at x=4 is y= 3/25 x+23/25

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tangent of f(x)=(2x-1)/(x+1),\at x=4

tangent of

f (x) = \frac{2 x - 1}{x + 1}, at x = 4

y = \frac{3}{25} x + \frac{23}{25}

Solution steps

Find the tangent point:

(4, \frac{7}{5})

Find the slope of

f (x) = \frac{2 x - 1}{x + 1} : \frac{df ( x )}{d x} = \frac{3}{( x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{2 x - 1}{x + 1}

x = 4 : m = \frac{3}{25}

Find the line with slope m=

\frac{3}{25}

and passing through

(4, \frac{7}{5}) : y = \frac{3}{25} x + \frac{23}{25}

y = \frac{3}{25} x + \frac{23}{25}

\int (x + \frac{1}{x})^{\frac{3}{2}} (\frac{x ^{2} - 1}{x ^{2}}) d x

\frac{\partial}{\partial y} (7 x^{2} + e^{2 y})

\int 4 x (x^{2} + 26000)^{- \frac{2}{3}} d x

f (x) = (x - 4) (3 - x)^{3}

\frac{d}{d x} ((x - 2)^{2} \cdot (x + 4))

What is the tangent of f(x)=(2x-1)/(x+1),\at x=4 ?
The tangent of f(x)=(2x-1)/(x+1),\at x=4 is y= 3/25 x+23/25