What is the derivative of y=sqrt(x^2+3) ?

The derivative of y=sqrt(x^2+3) is x/(sqrt(x^2+3))

What is the first derivative of y=sqrt(x^2+3) ?

The first derivative of y=sqrt(x^2+3) is x/(sqrt(x^2+3))

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derivative of

y = x^{2} + 3

\frac{x}{x ^{2} + 3}

Solution steps

\frac{d}{d x} (x^{2} + 3)

Apply the chain rule:

\frac{1}{2 x ^{2} + 3} \frac{d}{d x} (x^{2} + 3)

= \frac{1}{2 x ^{2} + 3} \frac{d}{d x} (x^{2} + 3)

\frac{d}{d x} (x^{2} + 3) = 2 x

= \frac{1}{2 x ^{2} + 3} \cdot 2 x

Simplify

\frac{1}{2 x ^{2} + 3} \cdot 2 x : \frac{x}{x ^{2} + 3}

= \frac{x}{x ^{2} + 3}

\int_{1}^{4} \frac{7}{x ^{2}} d x

(9 x + 3) + (9 y - 9) y^{^{'}} = 0

\int_{0}^{3} (x + 9 - x^{2}) d x

\int_{1}^{2} cos (x^{2}) d x

\frac{\partial}{\partial y} (x^{2} + x y)

What is the derivative of y=sqrt(x^2+3) ?
The derivative of y=sqrt(x^2+3) is x/(sqrt(x^2+3))
What is the first derivative of y=sqrt(x^2+3) ?
The first derivative of y=sqrt(x^2+3) is x/(sqrt(x^2+3))