What is (\partial)/(\partial y)(2y-x) ?

The answer to (\partial)/(\partial y)(2y-x) is 2

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(\partial)/(\partial y)(2y-x)

\frac{\partial}{\partial y} (2 y - x)

2

Solution steps

\frac{\partial}{\partial y} (2 y - x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 y) - \frac{\partial}{\partial y} (x)

\frac{\partial}{\partial y} (2 y) = 2

\frac{\partial}{\partial y} (x) = 0

= 2 - 0

Simplify

= 2

\int x^{2} (5 + 2 x^{3})^{8} d x

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\int \frac{5}{x ^{5}} d x

\int 2 e^{c o s (x)} sin (x) d x

What is (\partial)/(\partial y)(2y-x) ?
The answer to (\partial)/(\partial y)(2y-x) is 2