What is the derivative of xy+1 ?

The derivative of xy+1 is x(dy)/(dx)+y

What is the first derivative of xy+1 ?

The first derivative of xy+1 is x(dy)/(dx)+y

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\frac{d}{d x} (x y + 1)

x \frac{d y}{d x} + y

Solution steps

\frac{d}{d x} (x y + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x y) + \frac{d}{d x} (1)

\frac{d}{d x} (x y) = y + x \frac{d y}{d x}

\frac{d}{d x} (1) = 0

= y + x \frac{d y}{d x} + 0

Simplify

= x \frac{d y}{d x} + y

\frac{d}{d x} (3 (sin (2 x) cos (x) - sin^{3} (x)))

\int_{0}^{3} x x^{2} + 1 d x

\int \frac{1}{20 - y} d y

\frac{d}{d x} (sin (ln (x)) + cos (ln (x)))

f (x) = - 3 x^{3}

What is the derivative of xy+1 ?
The derivative of xy+1 is x(dy)/(dx)+y
What is the first derivative of xy+1 ?
The first derivative of xy+1 is x(dy)/(dx)+y