What is the solution for y^'=3y-y^2 ?

The solution for y^'=3y-y^2 is y=-(3e^{3t+3c_{1}})/(1-e^{3(t+c_{1))}}

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y^'=3y-y^2

y^{^{'}} = 3 y - y^{2}

y = - \frac{3 e ^{3 t + 3 c_{1}}}{1 - e ^{3 (t + c_{1})}}

Solution steps

y^{'} (t) = 3 y - y^{2}

Solve separable ODE:

y = - \frac{3 e ^{3 t + 3 c_{1}}}{1 - e ^{3 (t + c_{1})}}

y = - \frac{3 e ^{3 t + 3 c_{1}}}{1 - e ^{3 (t + c_{1})}}

c x

y^{^{'}} - \frac{4}{x} y = \frac{y ^{3}}{x ^{3}}, y (1) = 1

\frac{d}{d x} (\frac{7}{10} x^{2} + 4 x^{3})

\frac{d y}{d x} - y = - \frac{x}{2}

x \to 0 lim (1 - \frac{1}{x ^{2}})

What is the solution for y^'=3y-y^2 ?
The solution for y^'=3y-y^2 is y=-(3e^{3t+3c_{1}})/(1-e^{3(t+c_{1))}}