What is join (ax^2)/(ln(x/4))+(bx^4)/(x-4) ?

The solution to join (ax^2)/(ln(x/4))+(bx^4)/(x-4) is (ax^2(x-4)+bx^4ln(x/4))/(ln(x/4)(x-4))

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join (ax^2)/(ln(x/4))+(bx^4)/(x-4)

join

\frac{a x ^{2}}{ln ( \frac{x}{4} )} + \frac{b x ^{4}}{x - 4}

\frac{a x ^{2} ( x - 4 ) + b x ^{4} ln ( \frac{x}{4} )}{ln ( \frac{x}{4} ) ( x - 4 )}

Solution steps

\frac{a x ^{2}}{ln ( \frac{x}{4} )} + \frac{b x ^{4}}{x - 4}

Least Common Multiplier of

ln (\frac{x}{4}), x - 4 : ln (\frac{x}{4}) (x - 4)

Adjust Fractions based on the LCM

= \frac{a x ^{2} ( x - 4 )}{ln ( \frac{x}{4} ) ( x - 4 )} + \frac{b x ^{4} ln ( \frac{x}{4} )}{( x - 4 ) ln ( \frac{x}{4} )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{a x ^{2} ( x - 4 ) + b x ^{4} ln ( \frac{x}{4} )}{ln ( \frac{x}{4} ) ( x - 4 )}

\frac{\partial}{\partial x} (3 x^{2} y^{2} - 1)

x^{2} - 1

n = 2 \sum \infty \frac{1}{n ( n + 1 )}

\int x^{\frac{- 2}{3}} x^{\frac{1}{3}} - 2 d x

\int \frac{d s}{s ^{2} ( s - 1 ) ^{2}} d x

What is join (ax^2)/(ln(x/4))+(bx^4)/(x-4) ?
The solution to join (ax^2)/(ln(x/4))+(bx^4)/(x-4) is (ax^2(x-4)+bx^4ln(x/4))/(ln(x/4)(x-4))