What is the solution for (dy)/(dx)=y(c_{1}+pi^2)(1+x)^{-1} ?

The solution for (dy)/(dx)=y(c_{1}+pi^2)(1+x)^{-1} is y=c_{1}(1+x)^{c_{1}+pi^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=y(c_{1}+pi^2)(1+x)^{-1}

\frac{d y}{d x} = y (c_{1} + π^{2}) (1 + x)^{- 1}

y = c_{1} (1 + x)^{c_{1} + π^{2}}

Solution steps

\frac{d y}{d x} = y (c_{1} + π^{2}) (1 + x)^{- 1}

Solve separable ODE:

y = c_{1} (1 + x)^{c_{1} + π^{2}}

y = c_{1} (1 + x)^{c_{1} + π^{2}}

\frac{d}{d x} (1 - cos (x))

\int sin (9 t) sin (4 t) d t

\frac{d}{d x} (2 x tan (2 x + 2))

y y^{^{'}} + y^{\frac{3}{2}} = 1

\frac{\partial}{\partial x} (ln (x^{7} - y^{6}))

What is the solution for (dy)/(dx)=y(c_{1}+pi^2)(1+x)^{-1} ?
The solution for (dy)/(dx)=y(c_{1}+pi^2)(1+x)^{-1} is y=c_{1}(1+x)^{c_{1}+pi^2}