What is the integral of arctan(1) ?

The integral of arctan(1) is pi/4 x+C

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integral of arctan(1)

\int arctan (1) d x

\frac{π}{4} x + C

Solution steps

\int arctan (1) d x

Integral of a constant:

\int a d x = a x

= arctan (1) x

Use the following trivial identity:

arctan (1) = \frac{π}{4}

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= \frac{π}{4} x

Add a constant to the solution

= \frac{π}{4} x + C

\frac{d}{d x} ((π - x) cos (x))

2 x^{2} - 4 x - 1

\frac{d}{d x} (e^{∣ x ∣})

\frac{\partial}{\partial x} (cos (x + 2 y))

y = (x^{3} - 9 x)^{8}, (3, 0)