What is the solution for (5x+ye^{(y/x)})dx-xe^{y/x}dy=0 ?

The solution for (5x+ye^{(y/x)})dx-xe^{y/x}dy=0 is y=ln(5ln(x)+c_{1})x

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(5x+ye^{(y/x)})dx-xe^{y/x}dy=0

(5 x + y e^{(\frac{y}{x})}) d x - x e^{\frac{y}{x}} d y = 0

y = ln (5 ln (x) + c_{1}) x

Solution steps

(5 x + y e^{(\frac{y}{x})}) d x - x e^{\frac{y}{x}} d y = 0

Solve using substitution:

y = ln (5 ln (x) + c_{1}) x

y = ln (5 ln (x) + c_{1}) x

\frac{\partial}{\partial x} (ln (cos (x y) + 2))

\int tan^{4} (x) + tan^{6} (x) d x

h \to 0 lim (\frac{1}{5 - h})

\frac{e ^{- 2 s}}{s ( s - 1 )}

\frac{d}{d x} (- 2 x + 2)

What is the solution for (5x+ye^{(y/x)})dx-xe^{y/x}dy=0 ?
The solution for (5x+ye^{(y/x)})dx-xe^{y/x}dy=0 is y=ln(5ln(x)+c_{1})x