What is the solution for -10x^2y+y^'=9x^2 ?

The solution for -10x^2y+y^'=9x^2 is y=(e^{(10x^3+c_{1})/3})/(10)-9/10

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-10x^2y+y^'=9x^2

- 10 x^{2} y + y^{^{'}} = 9 x^{2}

y = \frac{e ^{\frac{10 x ^{3} + c _{1}}{3}}}{10} - \frac{9}{10}

Solution steps

- 10 x^{2} y + y^{'} (x) = 9 x^{2}

Solve separable ODE:

y = \frac{e ^{\frac{10 x ^{3} + c _{1}}{3}}}{10} - \frac{9}{10}

y = \frac{e ^{\frac{10 x ^{3} + c _{1}}{3}}}{10} - \frac{9}{10}

\int \frac{1}{3 ^{x} + 1} d x

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = - 3, y^{^{'}} (0) = 5

\frac{d y}{d x} = (x + 1)^{2}

\int_{1}^{3} (x + 2) (x - 1)^{5} d x

\frac{d}{d x} (\frac{- x ^{2} - 4 x - 1}{4 x - 3})

What is the solution for -10x^2y+y^'=9x^2 ?
The solution for -10x^2y+y^'=9x^2 is y=(e^{(10x^3+c_{1})/3})/(10)-9/10