What is the integral from 0 to 2 of ln(2x) ?

The integral from 0 to 2 of ln(2x) is 4ln(2)-2

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integral from 0 to 2 of ln(2x)

\int_{0}^{2} ln (2 x) d x

4 ln (2) - 2

Decimal Notation

0.77258 \dots

Solution steps

\int_{0}^{2} ln (2 x) d x

Apply Integration By Parts

: [x ln (2 x) - \int 1 d x]_{0}^{2}

= [x ln (2 x) - \int 1 d x]_{0}^{2}

\int 1 d x = x

= [x ln (2 x) - x]_{0}^{2}

Compute the boundaries:

4 ln (2) - 2

= 4 ln (2) - 2

\frac{\partial}{\partial x} (\frac{y}{ln ( x - 1 )})

\frac{d y}{d t} + a y = 0

2 y^{^{'}} + x y^{^{''}} = 0

\frac{\partial}{\partial z} (2 x)

\int 4 x sec^{2} (2 x) d x

What is the integral from 0 to 2 of ln(2x) ?
The integral from 0 to 2 of ln(2x) is 4ln(2)-2