What is the integral of x-\sqrt[4]{x} ?

The integral of x-\sqrt[4]{x} is (x^2)/2-4/5 x^{5/4}+C

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integral of x-\sqrt[4]{x}

\frac{x ^{2}}{2} - \frac{4}{5} x^{\frac{5}{4}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int x d x = \frac{x ^{2}}{2}

= \frac{x ^{2}}{2} - \frac{4}{5} x^{\frac{5}{4}}

Add a constant to the solution

= \frac{x ^{2}}{2} - \frac{4}{5} x^{\frac{5}{4}} + C

\frac{- 5 e ^{(- s)}}{( s ^{2} + 6 s + 25 )}

f (x) = ln (sech (2 x))

\int x^{2} sin (3 x) d x

\frac{d y}{d x} = tan^{2} (x)

\frac{d ^{2}}{d x ^{2}} (\frac{3 x + 4}{2 x - 5})

What is the integral of x-\sqrt[4]{x} ?
The integral of x-\sqrt[4]{x} is (x^2)/2-4/5 x^{5/4}+C